The point is that if there is a polynomial with real coefficients has a complex solution, then the

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The point is that if there is a polynomial with real coefficients has a complex solution, then the solution is also linked to this is the solution. Proof: Suppose that there is a polynomial with real coefficients, ie we assume that exists, that is. We can also register. Closely linked to the sum is the sum. We prove it for two complex numbers we conclude this induction. There are two complex numbers and. The numbers adjacent to them are and. The amount is indexed. The amount is indexed. If so, can we write our equation is. Now we prove that, when any real t -. The product of the suite is adjacent to the Patriarchs. We will show for two numbers and we conclude from the specific to the general. There are two complex numbers and. The numbers adjacent to them are and. Hem is linked. Adjacent to the Patriarchs is. From this we can write. Now we can write down, that is therefore whether vma 2011 the polynomial has real coefficients has a complex solution z, then also linked to z is a solution.
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