Can help please?

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Can help please?
I have an idea how to solve but I have the final answers ema wales please Edit: I found the book so I have the answers to a. Triangle ABC angle ACB is equal because the sum angles in triangle ABC. Triangle ABC Trial sinuses do: and after simplifications to find the radius. In. At first we reduce the height to the base ABC SO. Because the pyramid straight then height meets the base at the center of the circle circumscribes the base. We denote the angle gamma they asked angle between the trade side SC base. Desired angle is the angle gamma SCO. Since O is the center of the circle circumscribes the base then the radius blocks is OC, which we found in section. We have the OC. SOC triangle tangent ema wales users to find the height: set the OC Section A expression and find the SO. Now we have the height of the pyramid, can calculate the area of the base by the side of the square and next to two angles sine (if you want I would be considered the area) so come and inflate. C. Deduct plumb from S to BC triangle SBC. Point of intersection of the vertical with BC is E. According to court three colures ema wales (if you do not know the law has its explanation in human Goren on page 230) section OE also be perpendicular to BC. Therefore OE perpendicular to BC. Desired angle is the angle SEO. By the posts of the given angle we can calculate the SO and OC (of course with c.) If alpha and beta equal to 60 then the triangle ABC is equilateral, which means that the rib BC is equal to c. Triple SBC isosceles that pyramid straight, so the height SE Cross the base BC, so BE = CE = 0.5c. triangle OEC do Pythagorean Theorem and find the OE. remains to make a triangle tangent SEO and find the required angle. whether there was anything unclear you should explain just say, good luck
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